Solve 3n^2+17n+10=0 a. n = -2/3 or n = -5 b. n = -2/3 or n = 3 c. n = 0 or n = 5 d. n = -5 or n = 3

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asked Jun 10, 2019 175k views

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Solve 3n^2+17n+10=0

a. n = -2/3 or n = -5
b. n = -2/3 or n = 3
c. n = 0 or n = 5
d. n = -5 or n = 3

Mathematics
high-school

Laaouatni Anas asked

by Laaouatni Anas

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$3n^2+17n+10=0\\\\3n^2+15n+2n+10=0\\\\3n(n+5)+2(n+5)=0\\\\(n+5)(3n+2)=0\iff n+5=0\ \vee\ 3n+2=0\\\\n=-5\ \vee\ n=-(2)/(3)$

$Answer:\ a.\ n=-(2)/(3)\ or\ n=-5$

Uniquelau answered Jun 16, 2019

by Uniquelau

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