Question

2. -3n(2n – 5) = 0

a. n = 2 or n = 0
b. n = -5 or n = -3
c. n = 0 or n = 5/2
d. n = 2/5 or n = -3

Answer 1

`-3n(2n-5)=0\iff -3n=0\ \vee\ 2n-5=0\\\\-3n=0\ \ \ |:(-3)\\n=0\\\\2n-5=0\ \ \ \ |+5\\2n=5\ \ \ |:2\\n=(5)/(2)`


`Answer:\ c.\ n=0\ or\ n=(5)/(2)`

Answer 2

altho' it's rather obvious what you're supposed to do here, I'd suggest you always include all of the instructions.

-3n(2n – 5) = 0 is easily solved. Ignore the coefficient -3. Then you have n(2n-5)=0 Then either n=0 or 2n=5, which results in n=0 and n = 5/2 (solutions).