Question

A gas occupies 1.00 L at standard temperature. What is the volume at 606 K?

0.0222
0.222
2.22
22.2.

Answer 1

the volume at 606k is 2.22....the third one

Explanation:

v1=1.00 t1=273 v2=? t2=606

v1/t1=v2/t2

1.00/273=v2/606

1.00×606=273v2

606=273v2

606/273=v2

2.21 L=v2