Answer:
Let two integers be x and y.
Consider x > y
The sum of two integers is 74.
⇒ x+y = 74 .....[1]
It is also given that: The larger is 26 more than twice the smaller
⇒x = 2y +26 ......[2]
Substitute equation [2] into [1] we have;
![2y+26+y = 74](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p47t2abdextjh3v7608zsoohs5tw937b8e.png)
Combine like terms;
![3y+26= 74](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nzoksk0lwv2uq1imnks1jqrlbk6ph8jszc.png)
Subtract 26 from both sides we have;
3y = 48
Divide both sides by 3 we have;
y = 16
Substitute the value of y in [2] we have;
x = 2(16)+26 = 32+26
x = 58
Therefore, the two integers are 58 and 16