Hey there! :)
![6√(3) + 5 √(12)](https://img.qammunity.org/2019/formulas/mathematics/high-school/7xotshrssxph3vgfzw7i3qufdd9iim36fp.png)
In order to add these together, we must simplify the square roots.
![6 √(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ov25g1gsunkwozwkeg5usdwr2jn9tlaiqq.png)
is already in simplest terms, but
![5 √(12)](https://img.qammunity.org/2019/formulas/mathematics/high-school/g4f2md4pqfcxtwe2hofb1sbiv2u4mqqhl9.png)
is not.
So, let's start simplifying it!
![√(12) = ?](https://img.qammunity.org/2019/formulas/mathematics/high-school/n6tl46yrqde0tzvvv4r79dfwd4a8m3qgw8.png)
We need to take out any squares within 12.
So, if we branch out 12, we know that 4 × 3 = 12
√4 = 2. So, we can take out 2 and be left with √3.
Since the original square is 5√12, we MUST multiply 5 by 2.
![5*2 √(3) = 10 √(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5ayqyufjbfaup8w2qfa01ctz05932xik08.png)
So, using the simplified number of 5 root 12, we now can add this to 6 root 3.
![6 √(3) + 10 √(3) = 16 √(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5iq87k0ifwcm138yjkiis9k3fyguk5fzps.png)
So, our final answer is :
![16 √(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/o5yo53q8w6ejx4ey9740c1wwslx0g425if.png)
~Hope I helped!~