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Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of water every day. How many liters of oats and water do the horses consume in one week combined?

User Moobaa
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2 Answers

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19 liters and 2 deciliters =192 deciliter and 464 deciliter adding them we have 65 liters and 6 deciliters.
User Alan Smith
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Answer:

459.2 liters.

Explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.


\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}


\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}

46 liters=46*10=460 deciliters


\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}


\text{Total amount of water consumed per day}=464\text{ deciliters}

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.


\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}


\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}


\text{Total weekly consumption of oats and water}=4592\text{ deciliters}

Let us convert weekly consumption of water and oats into liters.


\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}


\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}


\text{Total weekly consumption of oats and water}=(4592)/(10)\text{ liters}


\text{Total weekly consumption of oats and water}=459.2\text{ liters}

Therefore, total weekly combined consumption of oats and water is 459.2 liters.

User Remi Deprez
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