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Assume the total cost of a college education will be $380,000 when your child enters college in 16 years. you presently have $62,000 to invest. what annual rate of interest must you earn on your investment to cover the cost of your child's college education? (do not round intermediate calculations and enter your answer as a percent rounded to 2 decimal places,

e.g., 32.16.)

User Careem
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4 votes

Final answer:

To cover the cost of a child's college education in 16 years at a total cost of $380,000 starting with an investment of $62,000, an annual rate of interest of approximately 7.46% is required.

Step-by-step explanation:

To find the annual rate of interest necessary to grow an investment of $62,000 to $380,000 in 16 years, we can use the formula for compound interest. The formula we need is the Future Value formula for compound interest which is FV = PV(1 + r)^n, where FV is the future value of the investment, PV is the present value, r is the annual interest rate, and n is the number of years.

Here, the future value (FV) is $380,000, the present value (PV) is $62,000, and the number of years (n) is 16. We're solving for the rate (r).

By rearranging the formula to solve for r, we have r = ((FV/PV)^(1/n)) - 1. Plugging in the numbers we get r = (($380,000 / $62,000)^(1/16)) - 1.

After calculating the result, we find that the annual rate of interest required is approximately r = 0.0746 or 7.46% when rounded to two decimal places.

User Geofftnz
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3 votes
Annual interest rate
(380,000÷62,000)^(1÷16)−1
=0.1199×100=11.99%
User Yehuda
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