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What is the equation for a circle that has a center at -6,5 and passes through the point -11,3?
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What is the equation for a circle that has a center at -6,5 and passes through the point -11,3?

User Hero
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(x + 6)² + (y - 5)² = r²
(-11+6)² + (3-5)² = r²
(-5)² + (-2)² = r²
25 + 4 = r²
29 = r²

Answer: (x + 6)² + (y - 5)² = 29
User ThomasFey
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