Question

Suppose that 37.4% of all college football teams had winning records in 1998, and another 24.8% broke even. What is the probability that a randomly chosen college football team had a losing record in 1998?

Answer 1

Let’s say there are 1000 football teams.

Having winning records in 1998-> 374
Broke the winning records-> 248


Losing record-> 1000-374-248=378

Total=1000

-> 37.8% (378/1000 *100)

Answer 2

0.378

Explanation:

Given that 37.4% of all college football teams had winning records in 1998, and another 24.8% broke even

i.e.if total college students are 100, 37.4 will win and 24.8 will break even

(Here we should not take literally decimals because these are examples.)

Losers
`= 100-37.4-24.8 = 100-62.2 = 37.8`

Hence probability that a randomly chosen college football team had a losing record in 1998

`=37.8%\\=0.378`