Help please!!! What is P(0.6 ≤ z ≤ 2.12)? 16% 26% 73% 98%

Question

asked Mar 1, 2019 55.8k views

2 Answers

Karl Wilbur · Answer 1 · 2019-03-07T13:10:11+0000

Answer:

The correct option is 2.

Explanation:

We have to find the value of P(0.6 ≤ z ≤ 2.12).

$P(0.6\leq z\leq 2.12)=P(z\leq 2.12)-P(z< 0.6)$

From the Cumulative Standardized Normal Distribution table,

$P(z\leq 2.12)=0.9830$

P(z<0.6)=0.7257

$P(0.6\leq z\leq 2.12)=0.9830-0.7257$

$P(0.6\leq z\leq 2.12)=0.2573$

$P(0.6\leq z\leq 2.12)\approx 0.26=26\%$

Therefore the correct option is 2.