Question

A telegraph pole casts a shadow of 40 feet long when the angle of elevation for the sun is 63°. the pole leans 15° from the vertical, directly toward the sun. find the length of the pole. 37 ft 43 ft 79 ft 171 ft

Answer 1

The formulation of the problem is as shown in the attached photo. The height of the pole is h.

Using the sine rules;
40/Sin 12 = h/Sin 63

h = (40*Sin 63)/(Sin 12) = 171.42 ≈ 171 ft

Therefore, fourth option is the correct answer.

Answer 2

Answer: / A

171 ft / /

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Explanation: / / |

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/ / |

/ / P |

/ / |

/ / |

/ / |

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C /_63°__/_75°_______| B

40 ^

D

P = pole

First, you need to find the measure of angle CAD. Since supplementary angles add up to 180°, and we know one angle of it, 75°, you can do 180° - 75° = 105°. Then add 63° + 105 ° = 168°. Then subtract 180° - 168° = 12°. So angle CAD = 12 °.

Now, using the Sine Law, set up a proportion:

40 P

---------- = ---------- (cross multiply and divide by sin 12°) = 171.42 or 171.

sin 12° sin 63°

Hope this helps!

(BTW sorry if the picture looks confusing.)