Question

At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?

Answer 1

Answer: 321.6 K

Explanation: Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T` (At constant pressure and number of moles)

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1` = initial volume of gas = 0.432 L

`V_2` = final volume of gas = 0.550 L

`T_1` = initial temperature of gas =
`-20^oC=273-20=253K`

`T_2` = final temperature of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

`(0.432L)/(253K)=(0.550L)/(T_2)`

`T_2=321.6K`

Therefore, the final temperature will be 321.6 K.

Answer 2

the temperature that would the volume of a gas be 0.550l if it had a volume of 0.432 L at -20.0 c is calculated using the Charles law formula

that is v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l

by making T1 the subject of the formula T1= V1T2/V2


T1= (0.55lL x253)/ 0.432 l = 322.11 K or 322.11-273 = 49.11 C