Question

a test charge of -1.4 * 10-7 coulomb experience a force of 5.4 * 10^-1 Newtons. calculate the magnitude of the electric field created by the negative test charge.

Answer 1

3.6 × 106 newtons/coulomb

Answer 2

Charge (q) = -1.4 x 10^-7 Coulombs
Force (F) = 5.4 x 10^-1 Newtons
Electric Field (E) = ?

Force = Charge x Electric Field

F = |q| x E
E = F / |q|
E = Newton/Coulomb <- Electric Field Unit

-> E = 5.4 x 10^-1 / |-1.4 x 10^-7|
-> E = 5.4 x 10^-1 / 1.4 x 10^-7
-> E = 3.857 x 10^(-1 - (-7))
-> E = 3.86 x 10^(-1+7)

-> E = 3.86 x 10^6 N/C

Answer: The magnitude of the electric field created is 3.86 x 10^6 N/C.