Question

A cylindrical rain barrel with a diameter of 3.5 feet and a height of 5.5 feet is filled to a height of 0.5 feet. How many more gallons of water can the barrel hold? Round your answer to the nearest whole number. (1 ft3≈7.5 gal)

Answer 1

361

Explanation:

I don't know how to do this but this is the answer my homework gave me

Answer 2

The volume of the barrel is given by:
V1 = (pi) * (r ^ 2) * (h)
Where,
r: barrel radio
h: height of the barrel
Substituting values we have:
V1 = (3.14) * ((3.5 / 2) ^ 2) * (5.5)
V1 = 52.89 feet ^ 3
The volume of the barrel up to a height of 0.5 feet is given by:
V2 = (3.14) * ((3.5 / 2) ^ 2) * (0.5)
V2 = 4.81 feet ^ 3
Subtracting both volumes we have:
V1-V2 = 52.89 - 4.81
V1-V2 = 48.08 feet ^ 3
In gallons we have:
V1-V2 = (48.08) * (7.5)
V1-V2 = 360.6 gallons
Round to the nearest whole number:
V1-V2 = 361 gallons
Answer:
the barrel can hold 361 more gallons