Answer:
The population would be 233 million ( approx )
Explanation:
Let the function that shows the population ( in millions ) after x years,

Suppose the population is estimated from 1995,
That is, for 1995,
x = 0,
Given, y = 228 for 1995,

Now, years from 1995 to 2001 = 6,
For x = 6, y = 230,



Hence, the equation that shows the given scenario is,

If x = 15,

Hence, the estimated population in 2010 would be 233.