Question

The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00 liter vessel. Upon analysis the following information was found: [NO2] = 0.5 M; [N2O4] = 0.025 M. Calculate the numerical value for the Keq of the N2O4 2NO2 system.

Answer 1

The numerical value for the Keq of the N2O4 ⇔ 2NO2 is 10 M

calculation
Keq = ( concentration NO)^2/ ( concentration of N2O4)


Keq= (0.5 )^2/0.025 = 10 M


The power of NO2 is taken as 2 as value 2 is is the one in front of No2 in equilibrium equation