Answer: A. 104.82 feet
Explanation:
You can observe in the figure a right triangle, where the height of the building is "x".
You need to use the identity:
![tan\alpha=(opposite)/(adjacent)](https://img.qammunity.org/2019/formulas/mathematics/college/4hgplqy9fffy9bp48ratd1kd8ikqjvxe88.png)
You can identify in the figure that:
![opposite=x\\adjacent=2,000\\\alpha=3\°](https://img.qammunity.org/2019/formulas/mathematics/college/29r3tiq41ot4odv3wqzlj5ylipi6sgj5xo.png)
Then, you can substitute these values into
:
![tan(3\°)=(x)/(2,000)](https://img.qammunity.org/2019/formulas/mathematics/college/lbz3yv5vqg3g6jpymf33xsrot8yvl2cjrm.png)
Solve for x:
![x=(2,000)(tan(3\°)\\x=104.815](https://img.qammunity.org/2019/formulas/mathematics/college/j7a8wr4fz7r1hst7cn4x4xmy86g87g7zfc.png)
Therefore, the height of the building to the nearest hundredth foot is:
104.82 feet