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4 votes
What is the following sum 2{^3 square root 16x^3y}+4{^3 square root 54x^6y^5}?

User Mseebach
by
5.7k points

2 Answers

4 votes

Answer:

B: 4x(
\sqrt[3]{2}y) + 12
x^(2)y (
\sqrt[3]{2}
y^(2))

Explanation:

took the test

User Daan Wilmer
by
5.6k points
2 votes

Answer:


4x\sqrt[3]{2y} +
12x^2y\sqrt[3]{2y^2}

Explanation:

Given expression
3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5}.

Let us simplify each of the radical separately first.


3\sqrt[3]{16x^3y}=3\sqrt[3]{2* 8 * x^3* y} =2\sqrt[3]{2} * \sqrt[3]{8} * \sqrt[3]{x^3} * \sqrt[3]{y}


=2\sqrt[3]{2} * 2* x* \sqrt[3]{y}

=
2* 2* x\sqrt[3]{2y}


= 4x\sqrt[3]{2y}


4\sqrt[3]{54x^6y^5}=4\sqrt[3]{2* 27 * x^3* x^3 * y^3* y^2} =4\sqrt[3]{2} * \sqrt[3]{27} * \sqrt[3]{x^3} * \sqrt[3]{x^3} * \sqrt[3]{y^3}*\sqrt[3]{y^2}


=4\sqrt[3]{2} * 3 * x* x * y * \sqrt[3]{y^2}


=12x^2y\sqrt[3]{2y^2}

Therefore,


3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5} =
4x\sqrt[3]{2y} +
12x^2y\sqrt[3]{2y^2}


User HMM
by
5.5k points
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