Question

What are the range values of the function f(x)=-3x2+5f(x)=-3x2+5 for the domain values {-2, 0, 1}?

Answer 1

To determine the range values of the function f(x) = -3x^2 + 5 for the domain values {-2, 0, 1}, we plug each value into the function and calculate the result, leading to the range values {-7, 5, 2}.

Step-by-step explanation:

To find the range values of the function f(x) = -3x2 + 5 for the domain values {-2, 0, 1}, we substitute each domain value into the function.

• For x = -2: f(-2) = -3(-2)2 + 5 = -3(4) + 5 = -12 + 5 = -7
• For x = 0: f(0) = -3(0)2 + 5 = 0 + 5 = 5
• For x = 1: f(1) = -3(1)2 + 5 = -3(1) + 5 = -3 + 5 = 2

Therefore, the range values for the given domain values are {-7, 5, 2}.

Answer 2

Put the values of x from domain to the equation of the function:


`f(x)=-3x^2+5\\\\for\ x=-2\to y=-3(-2)^2+5=-3(4)+5=-12+5=-7\\for\ x=0\to y=-3(0)^2+5=5\\for\ x=1\to y=-3(1)^2+5=-3+5=2`
Answer: {-7; 2; 5}