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The parabola whose equation is y 2 = 12x has directrix of:

x = 3
x = -3
y = 3
y = -3

User Trungduc
by
5.4k points

2 Answers

3 votes

Answer:

x=-3

Explanation:

The general equation of a parabola with vertex at the origin is


y^2=4ax

in the case that it opens horizontally and


x^2=4ay

in the case that it opens vertically. Moreover, in the case that the parabola opens horizontally, the point (0,a) is the focus of the parabola, and the directriz is the vertical line x=-a. The same is true but with interchanged coordinates for a parabola that open vertically.

In our case


y^2=12x=4\cdot3x

is a parabola that opens to the right with focus point (0,3) and vertical directriz

x=-3.

User Milan Cermak
by
5.8k points
0 votes
The parabola whose equation is y 2 = 12x has directrix of:
x = 3
x = -3
y = 3
y = -3

The directrix is:
x=-3

One way of solving is to assign values for x and y:
x y
0 0
1 3.46
1 -3.46
2 4.9
2 -4.9


When graphed, the solution is:
Direction: Opens RightVertex: (0,0)(0,0)Focus: (3,0)(3,0)Axis of Symmetry: y=0Directrix: x=−3
The parabola whose equation is y 2 = 12x has directrix of: x = 3 x = -3 y = 3 y = -3-example-1
User Ycannot
by
5.8k points