Question

the length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 77ft. Find the dimensions of the rectangle.

Answer 1

Let x = width
2x + 3 = length

Area of rectangle is length times width

x(2x + 3) = 77
2x² + 3x = 77
2x² + 3x - 77 = 0
2x² + 14x - 11x - 77 = 0
2x(x + 7) - 11(x + 7) = 0

(2x - 11)(x + 7) = 0

x = 11/2, - 7

Distance/measurements can't be negative so x = 11/2

The length:
2(11/2) + 3
11 + 3
14

Your width is 11/2 feet and your length is 14 feet.