Question

Does anyone know how to Graph f(x)=51(2)^x

Answer 1

f(x) = 102^x

Start with x=0.
f(0) = 102^(0) which is 1. Your y intercept (the line in the middle) is 0.

Your first point is (0,1).
For the second point, try x=1.

f(1) = 102^1 which is 102.
You second point is (1,102). Rinse and repeat. ;)

Answer 2

This is an exponential function.

If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.

Make a table and graph the points:

x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.

The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.