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write the sum using summation notation, assuming the suggested pattern continues. 3 - 15 + 75 - 375 + ...

2 Answers

6 votes

Answer:

summation of 3 times negative 5 to the power of n from n equals 0 to infinity

summation of 3 times 5 to the power of n from n equals 0 to infinity

Explanation:

User Rengers
by
5.5k points
7 votes

Answer:

Sn = ∑ 3(-5)^n, from n = 0 to n = n

Explanation:

* Lets study the geometric pattern

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5 , 10 , 20 , 40 , 80 , ………………………. (×2)

# 5000 , 1000 , 200 , 40 , …………………………(÷5)

* General term (nth term) of a Geometric pattern

- U1 = a , U2 = ar , U3 = ar^2 , U4 = ar^3 , U5 = ar^4

- Un = ar^n-1, where a is the first term , r is the constant ratio between

each two consecutive terms, n is the position of the number

# Ex: U5 = ar^4 , U7 = ar^6 , U10 = ar^9 , U12 = ar^11

- The sum of first n terms of a Geometric Pattern is calculate from

Sn = a(1 - r^n)/(1 - r)

- The summation notation is ∑ a r^n, from n = 0 to n = n

* Now lets solve the problem

∵ The terms if the sequence are:

3 , -15 , 75 , -375 , ........

∴ a = 3

∵ r = ar/a

∵ ar = -15 and a = 3

∴ r = -15/3 = -5

∵ Sn = a(1 - r^n)/(1 - r)

∴ Sn = 3[1 - (-5)^n]/[1 - (-5)] = 3[1 - (-5)^n]/6 = 1/2[1 - (-5)^n]

- By using summation notation

∵ Sn = ∑ a r^n , from n = 0 to n = n

∴ Sn = ∑ 3(-5)^n

User Mirodinho
by
5.2k points
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