Question

The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

Answer 1

Initial velocity means that the time will be 0 seconds.

We must derive the equation first to find velocity:


`(d)/(dt) -16t^(2) + 19t + 110`

`-32t + 19`

Because we're looking for initial velocity, t = 0. Plug this into the equation:


`-32(0) + 19`

`0 + 19 = 19`

The initial velocity of the rock thrown is 19 feet per second.