Question

The solubility of gas is 0.58 g/L at a pressure of 104 kPa. What is the solubility if it’s solubility pressure increases to 250 kPa at the same temperature?

Answer 1

Converting to pascal
104/1000=0.104=P1
250/1000=0.25=P2
If 0.58=0.104
=0.25
Cross multiply
Solubility =[0.58*0.25]/0.104=1.39g/l

Answer 2

Answer : The solubility of gas at pressure 250 kPa is, 1.39 g/L

Step-by-step explanation:

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

`S\propto P`

or,

`(S_1)/(S_2)=(P_1)/(P_2)`

where,

`S_1` = initial solubility of gas = 0.58 g/L

`S_2` = final solubility of gas = ?

`P_1` = initial pressure of gas = 104 kPa

`P_2` = final pressure of gas = 250 kPa

Now put all the given values in the above formula, we get the final solubility of the gas.

`(0.58g/L)/(S_2)=(104kPa)/(250kPa)`

`S_2=1.39g/L`

Therefore, the solubility of gas at pressure 250 kPa is, 1.39 g/L