We'll say that months = n.
Make a set of the DVD's sold:
![{20, 50, 80, 110, 140...}](https://img.qammunity.org/2019/formulas/mathematics/high-school/a9rb9wg6zekrcsdzlkergt41b5d23a5g68.png)
In month 1, Aaron sold 20 DVDs. There is no data for month 0.
There is a constant increase of 30 DVDs every month. We can make an equation out of this to fit this data set:
![a = 30n - 10](https://img.qammunity.org/2019/formulas/mathematics/high-school/3x57l9q26lyso2wxigmunnk7941mgs0xz9.png)
a represents the DVDs made.
We need to subtract 10 in this equation, as the starting point is 20, and the increase of 30 is different from the increase from n = 0 to n = 1.
We are looking for the amount of DVDs Aaron sold on the 13th month. Plug 13 into the equation:
![n = 13](https://img.qammunity.org/2019/formulas/mathematics/high-school/duw29ko0heb697dycpyvln1jc9mm5l71bg.png)
![30(13) - 10 = 390 - 10 = 380](https://img.qammunity.org/2019/formulas/mathematics/high-school/b2ea9tovycr58yiu9gq4t44zay41qdwnrt.png)
The predicted number of DVDs Aaron will sell on the 13th month is
380.