Question

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = -16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is 144 a0 feet.

Answer 1

For this case we have the following equation:
h = -16t2 + 64t + 80
To find the maximum height, we derive the equation:
h = -32t + 64
We match zero:
-32t + 64 = 0
We clear t:
t = 64/32
t = 2
We substitute the value of t in the given equation:
h (2) = -16 * (2) ^ 2 + 64 * (2) + 80
h (2) = 144
Answer:
The maximum height is 144 feet and the time to reach this height is 2 seconds.