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Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. QS=

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6sqrt2 is the answer 
User Kiwimoisi
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the picture in the attached figure

we know that
RS=ST----------------> because is a square base
so
QS is the diagonal of the square base
applying the Pythagoras Theorem
QS²=RS²+ST²------> 6²+6²-----> QS²=72------> QS=√72----> QS=6√2 units

the answer is
QS=6√2 units
Given a regular square pyramid with RS = 6 and PX = 4, find the following measure-example-1
User Brett Gmoser
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