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A ship leaves port on a bearing of 34.0° and travels 10.4 miles. the ship then turns due east and travels 4.6 miles. how far is the ship from port, and what is its bearing from port?

User Brickpop
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2 Answers

6 votes

is a clockwise angle measured from due North. This is a problem, because all of the trigonometric functions are referenced to a counterclockwise angle measured from East.

A bearing of 34∘ corresponds to a trigonometric angle of θ1=90∘34∘=56∘

The (x,y) values for the position of the ship after completing its first heading are:

x=(10.4mi)cos(56∘)
y=(10.4mi)sin(56∘)

The trigonometric angle for the second heading is θ2=90∘90∘=0∘

The (x,y) values for the position of the ship after completing its second heading is:

x=(10.4mi)cos(56∘)+(4.6mi)cos(0∘)≈10.4mi
y=(10.4mi)sin(56∘)+(4.6mi)sin(0∘)≈8.6mi

The distance from port is:

d=(10.4)2+(8.6)2≈13.5mi

Its trigonometric angle is:

θ=tan−1(yx)

θ=tan−1(8.610.4)

θ≈39.6∘

The bearing angle is:

θb=90∘39.6∘=50.4

User Ehsan Rosdi
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8.3k points
1 vote

Answer:

C

Explanation:

A ship leaves port on a bearing of 34.0° and travels 10.4 miles. the ship then turns-example-1
User Dgebert
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8.0k points