We can see this is a summation of multiples of 8 plus 1, which starts at 1.
This can be written in the following way:

Lets verify the summation expression by doing the sequence for the first 4 elements (hence

, as it starts from 0):
![\Sigma_(m=0)^(3)(8m+1)=[8(0)+1]+[8(1)+1]+[8(2)+1]+[8(3)+1]=](https://img.qammunity.org/2019/formulas/mathematics/high-school/ptce0634mnuefdo3ykj0g01w59ranys914.png)

As you can see, the generalization is correct.