Answer : The correct option is, (A) The rock reached its closure temperature 6,400 years ago.
Explanation :
Half-life = 1600 years
First we have to calculate the rate constant, we use the formula :
![k=(0.693)/(t_(1/2))](https://img.qammunity.org/2019/formulas/biology/high-school/8efd9tonxuepcs3683fwlyi5g02opc4tj1.png)
![k=\frac{0.693}{1600\text{ years}}](https://img.qammunity.org/2019/formulas/biology/high-school/oykkg2fzauxiashotixqtdm6f9f6wd02wg.png)
![k=4.33* 10^(-4)\text{ years}^(-1)](https://img.qammunity.org/2019/formulas/biology/high-school/1k9w8c7z0hxj5je31ugs3latdyt9m1ncv0.png)
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
![t=(2.303)/(k)\log(a)/(a-x)](https://img.qammunity.org/2019/formulas/biology/high-school/1zz9efqb3ztmpmv1vmtzm2lfy6bswrh43h.png)
where,
k = rate constant =
![4.33* 10^(-4)\text{ years}^(-1)](https://img.qammunity.org/2019/formulas/biology/high-school/kq8nk8akp5lurxhgsjbovoyshewfgjjxmn.png)
t = time passed by the sample = ?
a = initial amount of the reactant = 6 g
a - x = amount left after decay process = 0.375 g
Now put all the given values in above equation, we get
![t=(2.303)/(4.33* 10^(-4))\log(6)/(0.375)](https://img.qammunity.org/2019/formulas/biology/high-school/m9kssngh028csby04one3oq9apo5rbrlkx.png)
![t=6404.36\text{ years}\approx 6400\text{ years}](https://img.qammunity.org/2019/formulas/biology/high-school/b9ch4g98uzgl7uh35s403vyo5a6znyol40.png)
Therefore, the correct option is, (A) The rock reached its closure temperature 6,400 years ago.