Question

A transformer on a 220 V line has 55 loops on the primary and 440 loops on the secondary and draws a 4.00 a current. Assuming no losses:

(A) what is the voltage from the secondary?
(B) what is the currency from the secondary?
(C) what is the power output?

Answer 1

For transfomers (robots in disguise), there are equations to help us solve these problems.

Here are the equations you need:


`(V_(p))/(V_(s))= (n_(p))/(n_(s))`


`V_(p)` is our V primary,
`v_(s)` is our V secondary,
`n_(p)` is our number of loops on our primary and
`n_(s)` is number of loops in our secondary.

Plugging our known values in, we can solve for the secondary voltage.


`(220)/(V_(s))= (55)/(440)`

`V_(s) = 1760V`

For current, we have another equation:


`V_(p)I_(p)=V_(s)I_(s)`

Just like before, we can plug in our known values:


`(220V)(4A)=(1760V)I_(s)`

`I_(s)= 0.5A`

Since we are told there are no losses, the input power must equal output power.

(0.5A)(1760V)=(220V)(4A) = 880W