147k views
3 votes
A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

f(t) = −16t2 + 32t + 384

The average rate of change of f(t) from t = 4 seconds to t = 6 seconds is :blank: feet per second.

2 Answers

2 votes
the answer for the blank is simply -128
User BlackHat
by
8.1k points
2 votes
For this case we have the following function:
f (t) = -16t2 + 32t + 384
By definition we have to:
The average rate of change:
AVR = (f (t2) - f (t1)) / (t2 - t1)
Where,
For t1 = 4
f (4) = -16 * (4) ^ 2 + 32 * (4) + 384
f (4) = 256
For t2 = 6
f (6) = -16 * (6) ^ 2 + 32 * (6) + 384
f (6) = 0
Substituting values we have:
AVR = (0 - 256) / (6 - 4)
AVR = -128
Answer:
The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is -128 feet per second.
User Xhirazi
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories