Question

if a 500.0-g block of metal absorbs 5,016J of heat when its temperature changes from 20.00 Celcius, what is the specific heat?

Answer 1

Correction: The temperature change is from 20 °C to 30 °C.

Answer:
Cp = 1.0032 J.g⁻¹.°C⁻¹

Solution:

The equation used for this problem is as follow,

Q = m Cp ΔT ----- (1)

Where;
Q = Heat = 5016 J

m = mass = 500 g

Cp = Specific Heat Capacity = ??

ΔT = Change in Temperature = 30 °C - 20 °C = 10 °C

Solving eq. 1 for Cp,

Cp = Q / m ΔT

Putting values,
Cp = 5016 J / (500 g × 10 °C)

Cp = 1.0032 J.g⁻¹.°C⁻¹