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If the image of a transformation is always ___ to the preimage the transformation is an isometry (fill in the blank, no options were given to me but I think it’s congruent... please help)
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If the image of a transformation is always ___ to the preimage the transformation is an isometry

(fill in the blank, no options were given to me but I think it’s congruent... please help)

User Randomishlying
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2 Answers

4 votes

I-think-it's-congruent-too.
User DeathByTensors
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8.3k points
3 votes
congruent is the correct answer.
User JusMalcolm
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8.4k points
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