What is the value of h when the function is converted to vertex form?

asked Feb 2, 2019 188k views

3 votes

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6 votes

$f(x)=ax^2+bx+c\\\\h=(-b)/(2a);\ k=f(h)$

We have:

$h(x)=x^2-8x+14\\\\a=1;\ b=-8;\ c=14$

Substitute:

$h=(-(-8))/(2\cdot1)=(8)/(2)=4$

Jaekyung answered Feb 3, 2019

6.7k points

3 votes

Completing the squqre:

h(x) = x^2 - 8x + 14 = x^2 - 8x + 16 - 16 + 14 = (x-4)^2 - 2

Here h=4 and k = -2.

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