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5y^2 - 2y - 7 are (5y - 7) and ( )

User Bdash
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1 Answer

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You have the following expression given in the problem above, which is a quadratic equation:

5y^2 - 2y - 7=0

When you factor the quadratic equation, you obtain the following form of it:
(5y - 7)(y +1)=0

Therefore, as you can see the answer is:
(5y - 7)(y +1)=0
User Denis Lins
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