Question

Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d=square root (3h/2), with d being the distance they can see in miles and h being their eye-level height in feet.

Answer 1

Answer: 3√5 mi.

Step-by-step explanation:

The formula is: d = √(3h/2)

Wyatt:

h = 120 ft

d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?

Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi

Answer 2

The formula is defined in the question as follows:


`d = \sqrt{ (3h)/(2) }`

h is the eye-level height.

Wyatt's eye-level height is 120. Plug this value into the equation:


`\sqrt{ (3(120))/(2) } = \sqrt{ (360)/(2) } = √(180) = 13.4164`

Shawn's eye-level height is 270. Plug this value into the equation:


`\sqrt{ (3(270))/(2) } = \sqrt{ (810)/(2) } = √(405) = 20.1246`

Subtract Wyatt's viewing distance from Shawn's to find their difference:


`20.1246 - 13.4164 = 6.7082`

Shawn can see 6.7082 miles farther than Wyatt.