Question

a 10 foot ladder is leaning up against a wall. The base of the ladder is 2 feet from the base of the building. How far up the building does the ladder fall?

Answer 1

see the picture attached to better understand the problem

we know that applying the Pythagoras Theorem
AC²=AB²+BC²
AC=10 ft
BC=2 ft
AB=?
AB²=AC²-BC²-----> 10²-2²-----> 100-4----> AC²=96
AC=√96 ft------> AC=9.80 ft

the answer is
9.80 ft