Question

Solve for e.

9e^2f=49

e=±√7f/3

e=±7√f/3

e=±7√f/3f

e=±√7f/3f

Answer 1

`9e^(2)f=49`
Divide by the coefficient of e², multiply by f/f, then take the square root.

`e^(2)=(49)/(9f)=(49)/(9f)\cdot (f)/(f)=(49f)/(9f^(2))\\\\e=\pm \frac{\sqrt{7^(2)f}}{\sqrt{(3f)^(2)}}\\\\e=\pm (7√(f))/(3f)`

The appropriate selection is ...
e = ±7√f/(3f)