Question

Question 10(Multiple Choice Worth 5 points)

(09.04 MC)

If (x + 1)2 = 55, what is the approximate positive value of x?

2.71
5.42
6.42
7.35

Answer 1

The answer is C, 6.42 :)

Answer 2

It is given in the question that

`(x+1)^2 = 55`

Now we need to get rid of square, and for that we take square root to both sides, that is

`\sqrt {(x+1)^2} = \pm √(55)`

`x+1 = -√(55) , x+1 = √(55)`

Subtracting 1 in both equations

`x = - √(55)-1 , x = √(55)-1 \\ x = -8.42 , 6.42`

Therefore , out of the given option, correct option is the third option