Question

Let E and F be two events that are mutually exclusive and suppose P(E)=.4 and P(F)=.2. Compute P(E intersect F)

Answer 1

Given that these two events are mutually exclusive, there's no any relation between them, so:


`P(E\cap F) = P(E)P(F)`

Then, the probability for this problem is given by:


`P(E\cap F) = (0.4)(0.2)=0.08`

Answer 2

P (E intersect F) refers to the probability of both events E and F happening at the same time. But since we are told that the events are mutually exclusive, it means that they cannot both occur simultaneously.

Therefore P (E intersect F) = 0