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Let E and F be two events that are mutually exclusive and suppose P(E)=.4 and P(F)=.2. Compute P(E intersect F)

User Ange Loron
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Given that these two events are mutually exclusive, there's no any relation between them, so:


P(E\cap F) = P(E)P(F)

Then, the probability for this problem is given by:


P(E\cap F) = (0.4)(0.2)=0.08

User Sahithi
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P (E intersect F) refers to the probability of both events E and F happening at the same time. But since we are told that the events are mutually exclusive, it means that they cannot both occur simultaneously.

Therefore P (E intersect F) = 0
User Tanmally
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