Question

The student council is sponsoring a concert as a fundraiser. Tickets are $3 for students and $5 for adults. The student council wants to raise at least $1,000. If 200 students attend how many adults must attend for them to get to their goal. write and solve an inequality

Answer 1

3S+5A≥1000
3(200)+5A≥1000
600+5A≥1000
-600 -600
5A≥400
-----------
5

A≥80
so 80 adults

Answer 2

There must attend at least 80 adults to raise at least $1,000.

Explanation:

Givens

• Tickets are $3 for students and $5 for adults.
• They want to raise at least $1,000. (Restriction).
• 200 students attended.

Let's call
`S` students and
`A` adults.

We know the benefits are restricted as

`3S+5A\geq 1000`

Because, they want to raise AT LEAST $1000, that's the minimum amount possible.

Now, we know that
`S=200`, replacing this value and solving for adults, we have

`3S+5A\geq 1000\\3(200)+5A\geq 1000\\600+5A\geq 1000\\5A\geq 1000-600\\5A\geq 400\\A \geq (400)/(5)\\ A\geq 80`

Therefore, there must attend at least 80 adults to raise at least $1,000.