19.1k views
2 votes
A 5.0g sample of aluminum with a specific heat of 0.90 j/g was heated from 22.1^c to 32.1^c. How much heat to the nearest joule did the aluminum gain?

User Thelem
by
7.7k points

1 Answer

4 votes
the heat to the nearest joules that aluminium gain is calculated as below

Q(heat) =M(mass) x c ( specific heat capacity) x delta T( change in temperature)
M=5.0 g
c=0.90 j/g/c
deltat T= 32.1 -22.1=10c

q= 5.0 g x 0.90 j/g/c x 10 c= 45 joules is the one gained by Alluminium


User Bufferz
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.