Quick answer: 5.4 pounds for a ball 3" in radius.RemarkYou are expected to do this by calling 4/3*pi = some constant k
Givensr = 2 inches
r1 = 3 inches
Ratio
Sub and solve Begin by cancelling out the ks.
![(W1)/(W2) = (r^3)/((r1)^3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/p23f14punsj5nqmcfwoxn5v9uf1wc1cj39.png)
Next substitute for the 2 rs.
![(W1)/(W2) = (2^3)/(3^3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/us0ezv49dgvol562lq1prwl0zu40ek350e.png)
Now expand the 2 cubic amounts.
Conclusion Part OneThe ratio of the two weights is 8/27
Part TwoSet up the ratio for 1.6 pounds to x
![(8)/(27) = (1.6)/(x)](https://img.qammunity.org/2019/formulas/mathematics/high-school/anj2czb9jrfvrwwxi2c16wgn4ehgfyhn8q.png)
Cross multiply
8*x = 27 * 1.6 Combine the right side.
8x = 43.2 Divide by 8
x = 43.2 / 8
x = 5.4 pounds.
If you take physics, you will do this quite frequently.