Question

What is the resulting pressure when you transfer gas from cylinder with a temperature of 22°C and the pressure of four atm into a container with a temperature of 65°C? Assume volume remains constant.

Answer 1

Answer:
P₂ = 4.58 atm

Solution:
According to Gay-Lussac's law ," the pressure of a given mass of an ideal gas at constant volume is directly proportional to absolute temperature".
For initial and final states of a gas, the relation is given as,

P₁ / T₁ = P₂ / T₂ ----- (1)

Data Given;
P₁ = 4 atm

T₁ = 22 °C + 273 = 295 K

P₂ = ??

T₂ = 65 °C + 273 = 338 K

Now, solving equation 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,

P₂ = (4 atm × 338 K) ÷ 295 K

P₂ = 4.58 atm