Question

How many moles of glucose, C H O , can be "burned" biologically when 18.2 mol of oxygen is available? C H O (s) + 6O (g) ---> 6CO (g) + 6H O(l) please show all the work

Answer 1

Answer: 18.2


Step-by-step explanation:

1) Chemical equation: C₆ H₁₂ O₆ (s) + 6O₂ (g) ---> 6CO₂ (g) + 6H₂O(l)

2) Mole ratio: 6 moles C₆ H₁₂ O₆ : 6 mol O₂

6:6 is the same that 1:1. This is, each molecule of C₆ H₁₂ O₆ is burned with one mole of O₂.

3) Conclusion:

Therefore, 18.2 moles of C₆ H₁₂ O₆ can be burned with 18.2 moles of O₂

Answer 2

Answer:
547.7 g of C₆H₁₂O₆

Solution:
The balance chemical equation is as follow,

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O

According to equation,

6 moles of O₂ burns = 180.56 g of C₆H₁₂O₆
So,
18.2 moles of O₂ will burn = X g of C₆H₁₂O₆

Solving for X,
X = (18.2 mol × 180.56 g) ÷ 6 mol

X = 547.7 g of C₆H₁₂O₆