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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find g(20) + ƒ(6).
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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find g(20) + ƒ(6).

User Mithun Sasidharan
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6.3k points

1 Answer

4 votes
ƒ(x ) = x² + 1
ƒ(6 ) = 6² + 1 =36+1=37

g(x ) = 3x + 1
g(20 ) = 3*20 + 1=61

g(20) + ƒ(6) = 37+61=98

g(20) + ƒ(6) =98
User Bharanitharan
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