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Using the law of cosines, what is m<X
61, 79, 82, 91

Using the law of cosines, what is m<X 61, 79, 82, 91-example-1
User Marcopeg
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2 Answers

6 votes

Answer:

B. 79

Step-by-step explanation:

Using the law of cosines, what is m<X 61, 79, 82, 91-example-1
User Suamere
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6.6k points
4 votes
Answer: 79°


Step-by-step explanation:


1) Law of cosines:


In a triangle with sides a, b, c whose opposite angles are, respectively, A, B and C, the law of cosines states:

c² = a² + b² - 2 a×b×cos (C)

2) In the triangle of the figure you have

c = 9
C = X
a = 6
b = 8
⇒ 9² = 6² + 8² - 2(6)(8) cos(X)
⇒ 81 = 36 + 64 - 96cos(X)
⇒ 96cos(X) = 36 + 64 - 81 = 19
⇒ cos(X) = 19 / 96
⇒ X = arccos(19/26) = 78.6° ≈ 79°

User Daniel Cho
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6.5k points
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