Question

Find the final pressure of a sample of gas at 1.3 atm and 1.9 l that is compressed to 158 ml

Answer 1

The final pressure of the gas is 15.6 atm (≅ 16 atm)

Step-by-step explanation:

Given:

Initial volume of the gas, V1 = 1.9 L

Initial pressure, P1 = 1.3 atm

Final volume of the gas, V2 = 158 ml = 0.158 L

To determine:

Final pressure, P2

Step-by-step explanation:

Based on the ideal gas equation

`PV = nRT`

where P = pressure, V = volume ; n = moles of gas

R = gas constant, T = temperature

At constant n and T, the above equation becomes:

PV = constant

This is the Boyle's law

Therefore:

`P1V1 = P2V2\\\\P2 = (P1V1)/(V2) = (1.3 atm*1.9 L)/(0.158L) =15.6 atm`

Answer 2

From the Boyle's law of gases; the volume of a fixed mass is inversely proportional to the pressure at constant temperature;
Therefore; PV is a constant
Thus; P1V1 =P2V2
1.3 × 1900 ml = P2 × 158 ml
P2 = (1.3 × 1900) ÷ 158 ml
= 15.63 atm